{"post":"

Program to find NcR NpR

nCr = n! / r!(n-r)!
\nnPr = n! / (n-r)!

Therefore, NPR= NCR*r!

Where C stands for Combinations, and P stands for permutation.

Algorithm

Prompt the user to input values for n and r using the cout and cin functions.
Create a function called factorial that takes an integer argument and returns a long int. Inside the function, use a loop to iterate over the range of values from 2 to the input argument, and calculate the factorial using a local variable.
In the main function, use the factorial function to calculate ncr as factorial(n) / (factorial(r) * factorial(n - r)), and npr as ncr * factorial(r).
Print the values of ncr and npr.

Code

#include <iostream>\n\nlong int factorial(int y) {\n    int i, fact = 1;\n    for (i = 2; i <= y; i++) {\n        fact = fact * i;\n    }\n    return fact;\n}\n\nint main() {\n    int n, r;\n    long int ncr, npr;\n\n    std::cout << \"Enter the value of n: \";\n    std::cin >> n;\n\n    std::cout << \"Enter the value of r: \";\n    std::cin >> r;\n\n    npr = factorial(n) / factorial(n - r);\n    ncr = npr / factorial(r);\n\n    std::cout << \"NCR value = \" << ncr << std::endl;\n    std::cout << \"NPR value = \" << npr << std::endl;\n\n    return 0;\n}\n\n

Output

Enter the value of n: 5\nEnter the value of r: 2\n\nNCR value = 10\nNPR value = 20\n\n

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