{"post":"

C++ program to find and print all unique elements of a given array of integers

Given: An array of integers, we have to find elements that are unique i.e., elements that are not repeated.

Example:

Given Array: [4, 12, 4, 2, 12, 20, 13]

Output: [2, 20, 13]

# Algorithm

Take the size and elements of the array as input from the user.
Initialize an array temp.
Find the repetition of each element and store it in the temp array.
After finding the repetition of each element, check if the repetition is 1. If so, print the element.

Code:

#include <iostream>\nusing namespace std;\n\nint main()\n{\n\n    int array[100], temp[100];\n    int n, i, j, cnt;\n    cout << \"Enter size of array: \";\n    cin >> n;\n    cout << \"\\nEnter elements in array: \";\n\n    for (i = 0; i < n; i++) {\n        cin >> array[i];\n        temp[i] = -1;\n    }\n\n    // Finding frequency of each element \n\n    for (i = 0; i < n; i++) {\n        cnt = 1;\n        for (j = i + 1; j < n; j++) {\n\n            if (array[i] == array[j]) {\n                cnt++;\n                temp[j] = 0;\n            }\n        }\n\n        if (temp[i] != 0) {\n            temp[i] = cnt;\n        }\n    }\n\n    // Printing all unique elements of the array\n    cout << \"\\nUnique elements present in the array are: \";\n    for (i = 0; i < n; i++) {\n        if (temp[i] == 1) {\n            cout << array[i] << \",  \";\n        }\n    }\n\n    return 0;\n}\n

Output

Enter size of array: 5\n\nEnter elements in array: 2 3 1 2 1\n\nUnique elements present in the array are: 3, \n\n

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