# Program to print all unique elements in an array

## C++ program to find and print all unique elements of a given array of integers

Given: An array of integers, we have to find elements that are unique i.e., elements that are not repeated.

Example:

Given Array: [4, 12, 4, 2, 12, 20, 13]

Output: [2, 20, 13]

### # Algorithm

1. Take the size and elements of the array as input from the user.
2. Initialize an array `temp`.
3. Find the repetition of each element and store it in the `temp` array.
4. After finding the repetition of each element, check if the repetition is 1. If so, print the element.

### Code:

``````#include <iostream>
using namespace std;

int main()
{

int array[100], temp[100];
int n, i, j, cnt;
cout << "Enter size of array: ";
cin >> n;
cout << "\nEnter elements in array: ";

for (i = 0; i < n; i++) {
cin >> array[i];
temp[i] = -1;
}

// Finding frequency of each element

for (i = 0; i < n; i++) {
cnt = 1;
for (j = i + 1; j < n; j++) {

if (array[i] == array[j]) {
cnt++;
temp[j] = 0;
}
}

if (temp[i] != 0) {
temp[i] = cnt;
}
}

// Printing all unique elements of the array
cout << "\nUnique elements present in the array are: ";
for (i = 0; i < n; i++) {
if (temp[i] == 1) {
cout << array[i] << ",  ";
}
}

return 0;
}
``````

Output

``````Enter size of array: 5

Enter elements in array: 2 3 1 2 1

Unique elements present in the array are: 3,

``````