Problem – Binary Number as a string, we have to print its 1’s complement.
1’s complement of a binary number is another binary number obtained by transforming all the 0 bit to 1 and the 1 bit to 0.
Example:
Input: 101010
One’s complement the number: 010101
Algorithm:
- Take binary number input as string having length say size.
- Initialize int fail=0.
- Start loop from i=0 to i<size
if binary[i]==1then comp[i]=0else if binary[i]==0
then comp[i]=1
else
print “error! Enter binary number of assigned size”
fail=1
break
- Put null character in the string complement
comp[size] = ‘\0’
- If fail ==0 then print the ones complement.
Code:
//Program to find one's complement of a binary number
#include <iostream>
#define size 6
using namespace std;
int main(){
int i, fail = 0;
char binary[size + 1], comp[size + 1];
cout << " Input a "<<size <<" bit binary number: ";
cin >> binary;
for (i = 0; i < size; i++) {
if (binary[i] == '1') {
comp[i] = '0';
}
else if (binary[i] == '0') {
comp[i] = '1';
} else {
cout << "Error! Input the number of assigned bits." << endl;
fail = 1;
break;
}
}
comp[size] = '\0';
if (fail == 0){
cout << "The original binary number = " << binary << endl;
cout << "Ones complement the number = " << comp << endl;
}
}Report Error/ Suggestion