{"post":"

Convert Binary to Octal program

Given: Binary number as input and we have to convert it to octal number.

This can be done by multiplying each digit of binary number starting from LSB with powers of 2 respectively, converting it to decimal and then diving it with 8 until it can be divided and print the reverse of remainder to get the octal value.

Example:

Binary number: 100101

(1*2^5) + (0*2^4)+ (0*2^3)+ (1*2^2)+ (0*2^1)+ (1*2^0) = 37

Decimal number =37

Divide 37 successively by 8 until the remainder is 0

37/8 = 4, remainder is 5

4/8 = 0, remainder is 4

Read from the bottom (MSB) to top (LSB) as 45

Octal number = 45

# Algorithm

Prompt the user to enter a binary number.
Iterate over the binary number from the least significant digit to the most significant digit, using a loop.
For each digit, multiply it by the corresponding power of 2 (using the counter variable as the exponent) and add the result to the overall result.
Divide the result by 8 and store the remainder.
Repeat step 5 until the result is 0.
Print the octal representation of the binary number by printing the remainder digits in reverse order.

Code:

#include <iostream>\n#include <math.h>\n\nusing namespace std;\n\nint main() {\n    // as binary numbers can be long\n    long binary, binaryinput;\n    int remainder, decimal_output, quotient, i, j, octal_output[100];\n\n    cout << \"Enter a binary number: \";\n    cin >> binaryinput;\n    binary = binaryinput;\n    i = 1;\n    decimal_output = 0;\n\n    // converting binary input to decimal\n    while (binaryinput > 0) {\n        remainder = binaryinput % 10;\n        decimal_output = decimal_output + remainder * i;\n        i = i + i;\n        binaryinput = binaryinput / 10;\n    }\n\n    i = 1;\n\n    // converting decimal to octal\n    quotient = decimal_output;\n    while (quotient > 0) {\n        octal_output[i++] = quotient % 8;\n        quotient = quotient / 8;\n    }\n\n    // printing the output\n    cout << \"The equivalent octal value of binary number \" << binary << \" is: \";\n    for (j = i - 1; j > 0; j--) {\n        cout << octal_output[j];\n    }\n\n    return 0;\n}\n\n

Output

Enter a binary number: 1010101\nThe equivalent octal value of binary number 1010101 is: 125\n\n

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