{"post":"

Convert Binary to Decimal program

Given: Binary number as input and we have to convert it to decimal number.

This can be done by multiplying each digit of binary number starting from LSB with powers of 2 respectively.

Example:

Binary number: 100101

(1*2^5) + (0*2^4)+ (0*2^3)+ (1*2^2)+ (0*2^1)+ (1*2^0) = 37

Decimal number =37

# Algorithm

Prompt the user to enter a binary number.
Initialize a variable result to 0.
For each digit in the binary number, starting from the least significant digit:\na. Multiply the digit by 2 raised to the power of its position in the number (starting from 0 for the least significant digit).\nb. Add the result of the multiplication to result.
Output the value of result as the decimal equivalent of the binary number.

Code:

#include <iostream>\n#include <math.h>\n\nusing namespace std;\n\nint main() {\n  long int i, no;\n  int x, result = 0;\n\n  cout << \"Enter any binary number: \";\n  cin >> no;\n\n  cout << \"\\nThe decimal conversion of \" << no << \" is \";\n\n  for (i = 0; no != 0; i++) {\n    x = no % 10;\n    result = (x) *(pow(2, i)) + result;\n    no = no / 10;\n  }\n\n  cout << result;\n\n  return 0;\n}\n

Output

Enter any binary number: 10101\nThe decimal conversion of 10101 is 21\n

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