Armstrong number in Python

Armstrong Number Program in Python

In this program where we are going to learn whether an N-digit integer is an Armstrong number or not.

A number is said to be an Armstrong number if it is equal to the sum of the cubes of its own digit.

Example: 153 is an Armstrong number, 153=1*1*1 + 5*5*5 + 3*3*3

Algorithm: 

1. Input from the user.
2. Take the length of the number.
3. Assign a = n
4. Initialize arm = 0.
5. Using for loop, find whether a given number is Armstrong or not.
6. Using if condition, if arm !=n then print it is not an Armstrong.
7. Else print it is an Armstrong number.
8. Exit 

Code:

n=input("Enter a number :")
l=len(n)
n=int(n)
a=n
arm=0
for i in range(l+1):
    b=a%10
    a=a/10
    arm=arm+(b**l)
if (arm != n):
    print("It is not an Armstrong no.")
else:
    print("It is an Armstrong no.")

Output: 

Enter a number :153
It is an Armstrong no.