Armstrong Numbers are numbers whose sum of individual digits raised to cubic power results in the original number.

Example: 153 = 1³+5³+3³=1+125+27 =153, thus 153 is an Armstrong Number.

The algorithm will be:

1. Enter and Store the Integer Input.
2. Create a duplicate of the input for later comparison.
3. Run a While loop construct such that it will run until the input is not reduced to 0.
4. Extract each individual digit of the input using Modulus Operator.
5. Perform Cumulative Sum of the Cubic Power of each digit extracted.
6. After the loop terminates, compare the duplicate of the user input with the cumulative sum.
7. If the result of comparison is true, the input is an Armstrong number.
8. Print the result accordingly.

import java.util.*;
class Armstrong
{
public static void main()
{
Scanner inp=new Scanner(System.in);
System.out.print("\n Enter Number: ");
int n=inp.nextInt();
int a,s=0,m=n;

while(n!=0)   // Extracting each digits and raising them to cubic power while accumulating its sum.
{
a=n%10;
s=s+(a*a*a);
n=n/10;
}

if(s==m)          // Checking if sum is equal to original number.
  System.out.println(m+" is an Armstrong Number");
else
  System.out.println(m+" is not an Armstrong Number");
  
}

}

Output:

Enter Number: 153
153 is an Armstrong Number

 Enter Number: 306
306 is not an Armstrong Number

Report Error/ Suggestion

Related Posts:

• Java Program to check vowel or consonant using if-else(ASCII)
• Java Program to delete all vowels from a string
• Java Program to print Pascal Triangle
• Java program to print inverted floyd’s triangle of any character
• Java program to add two matrices

[yuzo_views]