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Transpose of matrix in C++

JJuhi Kamdar1 min read

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The transpose of a matrix is obtained by interchanging its rows and column.

Algorithm:

1. Take input for number of rows and columns.

2. Interchange rows and columns.

Below given code doesn't use functions. It can also be written using functions.

Code:

#include<iostream>
using namespace std;
int row,col;
int main()
{
    int val,row,col;
    //insert rows and columns for matrix
    cin>>row;
    cin>>col;
    int a[row][col];
	//insert values in the matrix 
	cout<<"\n a: \n";
	for(int i=0;i<row;i++)
	{
		for(int j=0;j<col;j++)
		{
			cin>>val;
			a[i][j]=val;
		}
	}
//puting content of rows of a in columns of b
int b[col][row];
for(int j=0;j<row;j++)
{
for(int i=0;i<col;i++)
b[i][j]=a[j][i];
}
//copy contents of b in a
for(int i=0;i<col;i++)
{
for(int j=0;j<row;j++)
a[i][j]=b[i][j];
}

}

Output:

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