Transpose of matrix in C++

Written by

Juhi Kamdar

The transpose of a matrix is obtained by interchanging its rows and column.

Algorithm:

1. Take input for number of rows and columns.

2. Interchange rows and columns.

Below given code doesn’t use functions. It can also be written using functions.

Code:

``````#include<iostream>
using namespace std;
int row,col;
int main()
{
int val,row,col;
//insert rows and columns for matrix
cin>>row;
cin>>col;
int a[row][col];
//insert values in the matrix
cout<<"\n a: \n";
for(int i=0;i<row;i++)
{
for(int j=0;j<col;j++)
{
cin>>val;
a[i][j]=val;
}
}
//puting content of rows of a in columns of b
int b[col][row];
for(int j=0;j<row;j++)
{
for(int i=0;i<col;i++)
b[i][j]=a[j][i];
}
//copy contents of b in a
for(int i=0;i<col;i++)
{
for(int j=0;j<row;j++)
a[i][j]=b[i][j];
}
//display a
for(int i=0;i&lt;col;i++)
{
for(int j=0;j&lt;row;j++)
cout&lt;&lt;a[i][j]&lt;&lt;" ";
cout&lt;&lt;"\n";
}

return 0;

````}````

Output:

``````3 3
1 2 3
4 5 6
7 8 9
``````a: 1 4 7
2 5 8
3 6 9``````