Many a times, we require to find the number of digits in a number or the sum of all digits of a number. In such cases, we can use the following method:

**Algorithm:**

- First, save the number in another variable for future use.
- Now get the last digit of the number by using % operator. It will provide the last digit as remainder.
- We add it to the sum of all digits.
- Now, divide the Original number by 10, to trim the last digit. (This is possible as the data type is int)
- We repeat the above steps until all digits of the original number are summed up.

**Code:**

```
#include<iostream>
using namespace std;
int main()
{
int num,rem;
cin>>num;
int duplicatenum=num;
int sum=0, count=0;
while(num!=0) // till all digits of num are dealt with
{
rem=num%10; //remainder,last digit extracted
count++;
sum=sum+rem; // add rem to sum
num=num/10; //trimming last digit from num
}
cout<<"Sum of "<<duplicatenum <<" is "<<sum;
cout<<"\nNumber of digits are:"<<count;
return 0;
}
```

**Output:**

```
4567
Sum of 4657 is 22
Number of digits are:4
```

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