{"post":"

Many a times, we require to find the number of digits in a number or the sum of all digits of a number. In such cases, we can use the following method:

Algorithm:

First, save the number in another variable for future use.
Now get the last digit of the number by using % operator. It will provide the last digit as remainder.
We add it to the sum of all digits.
Now, divide the Original number by 10, to trim the last digit. (This is possible as the data type is int)
We repeat the above steps until all digits of the original number are summed up.

Code:

#include<iostream>\nusing namespace std;\nint main()\n{\nint num,rem;\ncin>>num;\nint duplicatenum=num;\nint sum=0, count=0;\nwhile(num!=0) // till all digits of num are dealt with\n{\nrem=num%10; //remainder,last digit extracted\ncount++;\nsum=sum+rem; // add rem to sum\nnum=num/10; //trimming last digit from num\n}\ncout<<\"Sum of \"<<duplicatenum <<\" is \"<<sum;\ncout<<\"\\nNumber of digits are:\"<<count;\nreturn 0;\n}

Output:

4567\nSum of 4657 is 22\nNumber of digits are:4

\n","title":"Program to find Sum of digits in C++","authorDetails":{"name":"Juhi Kamdar","slug":"juhi-kamdar"},"description":"Learn to write a program to find Sum of digits in C++ programming language using modulo operator.","slug":"cpp/examples/sum-of-digits-in-cpp/","articleId":"636a83457bb1ce5072622c19","bookmarkStatus":{"isBookmarked":false,"bookmarkId":null}}