Program to check odd or even in C++

Any number that can be perfectly divisible by 2 is known as an even number. While the one which does not divides by 2 perfectly is known as an odd number.

Perfectly divisible means, that the number on division produces 0 as remainder.

Algorithm:

1. Prompt the user to input a number.
2. Use the modulo operator (%) to check if the remainder of the number divided by 2 is 0.
3. Use an if statement to determine if the number is even or odd. If the remainder is 0, the number is even. Otherwise, it is odd.
4. Print a message indicating whether the number is even or odd.
5. Exit the program.

The below code checks if the integer entered by the user is even or odd:

#include <iostream>
using namespace std;
int main()
{
    int num;
    //Input the number
    cout<<"Enter an integer: ";
    cin>>num;
    if (num % 2 == 0)//check its divisibility with 2
         cout<< num << " is even.";
    else
        cout<< num <<" is odd.";
    return 0;
}

Output:

Enter an Integer:234

234 is even.