{"post":"

C++ Copy string program using pre-defined and user defined methods

Here we'll write a program to copy a string into another string.

In order to perform this, we can use one of the following methods:

Using predefined method strcpy()
Without using the predefined method/using user-defined function

Method 1: Using the predefined method

Logic: In this method, we'll use predefined function strcpy() which takes two arguments.

Strcpy(destination string, source string)

Note: This method does not return any value.

Algorithm:

Take a string input.
Initialize another string and name it newstr.
Call the function strcpy(new_string, old_string)
Print the new string, newstr.

Code:

#include<iostream,h>\n#include<string.h>\nvoid main()\n{\n\tstring str,newstr;\n\tcout<<\"Enter a string: \";\n\tgetline(cin,str);\n\tstrcpy(newstr, str);   //performing string copy\n\tcout<<\"The copied string is: \"<< newstr;\n}

Output:

Enter a string: Beijing\nThe copied string is: Beijing

Method 2: Without Using predefined method/Using user-defined method

Logic: In this method, we use the naïve approach of copying each character of a string in a new string using a loop.

Algorithm:

Take a string input and store it in str
Find and store the length of the string in a variable
Initialize another string and name it newstr.
Create a function which takes str and len as arguments and prints the copied string.
Print the new string, newstr.

Code:
\n

#include<iostream>\n#include<string>\nusing namespace std;\nvoid copy(string str, int len)\n{\n\tstring newstr;\n\tint i;\n\tfor(i=0; i<len; i++)//copying characters in newstr\n\t\tnewstr[i] = str[i]; //we can also use concatenation on an empty string\n\tnewstr[i] = '\\0'; //terminating string\n\tcout<<\"\\n The copied string is: \"<<newstr;\n}\nint main()\n{\n\tstring str;\n\tint len;\n\tcout<<\"Enter a string: \";\n\tgetline(cin,str);\n\tlen=str.length();\n\tcopy(str,len);\n\treturn 0;\n}

Output:

Enter a string: Studymite\nThe copied string is: Studymite

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