& Code
Here, We’ll check whether the given matrix is symmetrical or not. We’ll write a program in C to find the matrix is symmetric or not.
Note: The symmetry of a matrix can only be determined when it is a square matrix.
Logic: To find whether the matrix is symmetric or not we need to compare the original matrix with its transpose.
Algorithm:
- Take matrix input from the user.
- Then find the transpose of the matrix and store it.
- Now check if the original matrix is same as its transpose.
- If the original matrix is same as its transpose then the matrix is symmetric else its not symmetric.
Code:
#include <stdio.h>
int main()
{
int A[3][3], B[3][3];
int row, col, isSym;
// Take a matrix A as input from user
printf("Enter the elements in matrix of size 3x3: \n");
for(row=0; row<3; row++)
{
for(col=0; col<3; col++)
{
scanf("%d", &A[row][col]);
}
}
// Finds the transpose of matrix A
for(row=0; row<3; row++)
{
for(col=0; col<3; col++)
{
// Stores each row of matrix A to each column of matrix B
B[row][col] = A[col][row];
}
}
// Checks whether matrix A is equal to its transpose or not
isSym = 1;
for(row=0; row<3 && isSym; row++)
{
for(col=0; col<3; col++)
{
if(A[row][col] != B[row][col])
{
isSym = 0;
break;
}
}
}
// If the given matrix is symmetric.
if(isSym == 1)
{
printf("\n Matrix is Symmetric. \n");
for(row=0; row<3; row++)
{
for(col=0; col<3; col++)
{
printf("%d ", A[row][col]);
}
printf("\n");
}
}
else
{
printf("\n Matrix is not Symmetric.");
}
return 0;
}Output:
Enter elements in matrix of size 3×3:
1 2 3
3 4 5
4 5 6
Matrix is not Symmetric.Report Error/ Suggestion