{"post":"

Leap Year Program:

A leap year has 366 days whereas a non-leap year has 365 days.

To check if a year is a leap year it should satisfy either of the two conditions:

For years that are not century years (example – 2004, 2008, etc.), the year should be divisible by 4 and not divisible by 100 to be a leap year.
For years that are century years (example – 1600, 2000, etc.), the year should be divisible by 400 to be a leap year.

The code for checking if a year is a leap year or not is:

 \n#include <stdio.h>\nint  main() {
\nint  year;
\nprintf(\"Enter year: \");
\nscanf(\"%d\", & amp; year);
\nif  (((year % 4  == 0) & amp; & amp;\n(year % 100 != 0)) || (year % 400  == 0))
\n  printf(\"%d is a Leap year\", year);\n
\nelse
\n  printf(\"%d is not a Leap Year\", year);\n
\nreturn  0;
\n}
\n

We have created an integer variable year to store the user input for the year.
We are simply checking if the year is divisible by 4 and not divisible by 100 OR if the year is divisible by 400. If any of these two conditions are satisfied, the year is a leap year; else, it is not a leap year.
We use the modulus operator to check for divisibility. If a%b is equal to 0, it implies that a is perfectly divisible by b.

We run the code for different inputs and get the outputs accordingly.

Some inputs and outputs for the code are:

Enter year: 2002

2002 is not a Leap Year

Enter year: 2000

2000 is a Leap year

Enter year: 1993

1993 is not a Leap Year

Enter year: 1600

1600 is a Leap year

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