{"post":"

In this program, we are asked to enter a string and two integer values as indexes. Using these indexes, we will extract a substring from the string. The substring will be formed by iterating through the string from the starting index to the ending index - 1 and concatenating the characters onto a new string.

The logic for this process is as follows:

Prompt the user to enter a string and two integer indexes.
Validate the indexes to ensure they are within the bounds of the string. If the indexes are invalid, display an error message and exit the program.
Initialize an empty string variable to hold the extracted substring.
Iterate through the string from the starting index to the ending index - 1, adding each character to the substring variable.
Display the extracted substring to the user.

Code:

import java.util.*;\n\nclass SubString {\n  public static void main() {\n    Scanner inp = new Scanner(System.in);\n    System.out.print(\"\\n Enter String: \");\n    String s = inp.nextLine();\n    System.out.print(\"\\n Enter Starting Index: \");\n    int st = inp.nextInt();\n    System.out.print(\"\\n Enter Ending Index: \");\n    int en = inp.nextInt();\n\n    if (st < 0 || en > (s.length())) {\n      System.out.println(\"Invalid Index\");\n      System.exit(0);\n    }\n\n    int i, k = s.length();\n    String z = \"\";\n    char c;\n    for (i = st; i < en; i++) {\n      c = s.charAt(i);\n      z = z + c;\n    }\n\n    System.out.println(\"Extracted Substring: \" + z);\n  }\n}\n\n\n

Output:

  Enter String: ALMOST\n  Enter Starting Index: 2\n  Enter Ending Index: 5\n  Extracted Substring: MOS\n

\n","title":"Java Program to enter a string and extract its Substring","authorDetails":{"name":"Neha Vishwakarma","slug":"neha-vishwakarma"},"description":"Here, we are supposed to enter a String Input and input two integer inputs as index. Java Program to enter a string and extract its Substring.","slug":"java/examples/java-program-to-enter-a-string-and-extract-its-substring/","articleId":"636a83487bb1ce5072622c56","bookmarkStatus":{"isBookmarked":false,"bookmarkId":null}}