To get the sum of n numbers, there can be two cases:

1. Add consecutive n numbers.
2. Add any n numbers.

Method 1 – Sum of n consecutive numbers without an array(using while loop)

Algorithm:

1. Take input of n till which we need to get the sum.
2. Initialize a variable sum and declare it equal to 0(to remove garbage values).
3. Using while loop, add all numbers 1 to n.
4. Now, Print the sum.

Code:

#include<iostream>
using namespace std;
int main()
{
	int n,sum=0;
	cout<<"Enter number till which you would like to add";
	cin>>n;
	while(n>0)
	{
		sum+=n;
		n--;
	}
	cout<<"\n sum is:"<<sum;
	return 0;
}

Output:

Enter number till which you would like to add: 3

sum is:6

Method 2 – Sum of n numbers without an array(using while loop)

Code:

#include<iostream>
using namespace std;
int main()
{
	int n,sum=0,number;
	cout<<"How many numbers do you want to add?";
	cin>>n;
	cout<<"\n Enter numbers:";
	while(n>0)
	{
		cin>>number;
		sum+=number;
		n--;
	}
	cout<<"\n sum is:"<<sum;
	return 0;
}

Output:

How many numbers do you want to add? 7

Enter numbers:
1
2
3
4
5
89
34

Sum is:138

Method 3: sum of n numbers in array(using for loop)

Code:

#include<iostream>
using namespace std;
int main()
{
	int n,sum=0;
	cout<<"How many numbers do you want to add?";
	cin>>n;
	int arr[n];
	cout<<"\n Enter numbers:";
	
	for(int i=0;i<n;i++)
		cin>>arr[i];
	
	for(int i=0;i<n;i++)
		sum+=arr[i];
	
	cout<<"\n sum is:"<<sum;
	return 0;
}

Output:

How many numbers do you want to add? : 3

Enter numbers:
23
12
54

Sum is:89

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