Arithmetic Operators in C

Arithmetic Operators Examples:
C offers five binary operators and two unary operators.

Unary Operators:

++	This operator increases the value of the operand by 1.
– –	This operator decreases the value of the operand by 1.

The code snippet below shows how we can implement unary operators:

 
#include <stdio.h>
int  main(void) {
int  operand1 = 10;
int  operand2 = 5;
printf("Before using unary operators: \n");
printf("Value of operand1: %d \n", operand1);
printf("Value of operand2: %d \n", operand2);
operand1++; //incrementing operand1 by 1
operand2--; //decrementing operand2 by 1
printf("After using unary operators: \n");
printf("Value of operand1: %d \n", operand1);
printf("Value of operand2: %d \n", operand2);
return  0;
}

The output of the above code snippet will be:

Before using unary operators:

Value of operand1: 10

Value of operand2: 5

After using unary operators:

Value of operand1: 11

Value of operand2: 4

We have created two integer variables operand1 and operand2.
We increment the value of operand1 by 1.
We decrement the value of operand2 by 1.

Binary operators:

+	Adds two operands
–	Subtracts the second operand from the first operand
*	Multiplies two operands
/	Divides the first operand by the second operand
%	Gives the remainder left after dividing the first operand by the second operand

The code snippet below shows how we can implement binary operators:

 
#include <stdio.h>
int  main(void) {
int  operand1 = 10;
int  operand2 = 5;
int  sum = operand1 + operand2;
int  difference = operand1 - operand2;
int  product = operand1 * operand2;
int  quotient = operand1 / operand2;
int  remainder = operand1 % operand2;
printf("Value of operand1: %d \n", operand1);
printf("Value of operand2: %d \n", operand2);
printf("Results: \n");
printf("operand1 + operand2: %d \n", sum);
printf("operand1 - operand2: %d \n", difference);
printf("operand1 * operand2: %d \n", product);
printf("operand1 / operand2: %d \n", quotient);
printf("operand1 %% operand2: %d \n", remainder);
return  0;
}

The output of the above code snippet is:

Value of operand1: 10

Value of operand2: 5

Results:

operand1 + operand2: 15

operand1 - operand2: 5

operand1 * operand2: 50

operand1 / operand2: 2

operand1 % operand2: 0

We have created two integer variables operand1 and operand2.
We have used all binary operators i.e. +, -, *, / and %, on the two operands and we have got the expected results.